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AP Physics 2: Advanced Concepts & Calculations

Challenging flashcards covering advanced electrostatics, thermodynamics, fluid dynamics, and magnetic fields for AP Physics 2 mastery.

20 cards

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#1

Front

Define Electric Potential (V) physically and mathematically relative to a point charge.

Back

Electric potential V is the work done per unit charge to bring a small positive test charge from infinity to a specific point in the field against the electric force. For a point charge Q, V = kQ/r. Unlike electric field (a vector), V is a scalar field. Superposition applies algebraically: V_total = sum(kQ_i/r_i).

#2

Front

Equipotential Lines vs. Electric Field Lines relationship.

Back

Equipotential lines connect points of equal electric potential. Key relationships: 1) Electric field lines are always perpendicular to equipotential lines. 2) No work is required to move a charge along an equipotential surface (W = qΔV = 0). 3) In regions of strong electric fields, equipotential lines are packed closely together.

#3

Front

Derivation of the Capacitance for a Parallel Plate Capacitor.

Back

C = Q/ΔV. Using Gauss's Law, E = σ/ε₀ = Q/(Aε₀). Since E is uniform, ΔV = Ed = Qd/(Aε₀). Substituting ΔV into C = Q/ΔV gives C = Q / (Qd/Aε₀) = ε₀A/d. Capacitance depends only on geometry (Area A, distance d) and dielectric constant (ε), NOT on voltage or charge.

#4

Front

Dielectric Constant (κ) effect on Capacitor properties (C, V, Q, E).

Back

Inserting a dielectric material reduces the internal electric field (E = E₀/κ) and potential difference (ΔV = ΔV₀/κ) due to polarization of the material. Capacitance increases by factor κ: C = κC₀. If the capacitor is isolated (charge Q constant), voltage drops. If connected to a battery (V constant), charge stored increases by factor κ.

#5

Front

Internal Resistance (r) and Terminal Voltage in a Real Battery.

Back

Real batteries have internal resistance r. Terminal Voltage V_term = ε - Ir, where ε is emf and I is current. As current (load) increases, the voltage drop across the internal resistor (Ir) increases, decreasing the usable terminal voltage. If the circuit is open (I=0), V_term equals ε.

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