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IBDP Chemistry: Stoichiometry & Moles Core

Medium-difficulty flashcards covering the mole concept, empirical formulas, gas laws, and solution concentrations for IBDP Chemistry SL/HL.

20 cards

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#1

Front

The Mole Concept Definition

Back

The mole is the SI unit for amount of substance. One mole contains exactly 6.02214076 * 10^23 elementary entities (atoms, molecules, ions, etc.), known as Avogadro's constant (N_A). This number corresponds to the number of atoms in 12 grams of Carbon-12.

#2

Front

Calculating Moles from Mass

Back

Use the formula n = m / M, where n is the amount in moles, m is the mass in grams, and M is the molar mass in g/mol. Molar mass is calculated by summing the relative atomic masses (A_r) of all atoms in the chemical formula.

#3

Front

Empirical vs. Molecular Formula

Back

The **empirical formula** shows the simplest whole-number ratio of atoms of each element in a compound. The **molecular formula** shows the actual number of atoms of each element in a molecule. For example, glucose has an empirical formula of CH2O and a molecular formula of C6H12O6.

#4

Front

Determining Empirical Formula from Mass Data

Back

1. Convert mass of each element to moles (n = m/M). 2. Divide all mole values by the smallest number of moles calculated. 3. If the results are not whole numbers, multiply all by an integer to convert them to whole numbers (e.g., if you get 1.5, multiply all by 2).

#5

Front

Reacting Mass Calculations

Back

Use stoichiometric ratios from the balanced equation to convert moles of one substance to moles of another. Process: Mass A -> Moles A (divide by M_A) -> Moles B (multiply by mole ratio) -> Mass B (multiply by M_B).

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